By
Definition 9.2.5, we can prove that the set
\(\{\dots,-3,-2,-1\}\) of negative integers is countably infinite. It is enough to prove that
\(\{\dots,-3,-2,-1\}\) has the same cardinality as
\(\N\text{.}\)
By
Definition 9.1.4 we can prove that
\(\{\dots,-3,-2,-1\}\) has the same cardinality as
\(\N\) by building an invertible function from
\(\N\) to
\(\{\dots,-3,-2,-1\}\text{.}\)
Consider the function
\begin{equation*}
f:\N\to\{\dots,-3,-2,-1\} \text{ given by }f(x)=-x
\end{equation*}
and let
\begin{equation*}
g:\{\dots,-3,-2,-1\}\to\N \text{ given by }g(x)=-x\text{.}
\end{equation*}
Then we have
\begin{equation*}
(g\circ f)(x)= g(f(x)) = g(-x) = -(-x) = x
\end{equation*}
So
\((g\circ f)=\id_\N\text{.}\) By
Theorem 7.6.11 this means that
\(f\) is invertible. So we have found an invertible function from
\(\N\) to
\(\{\dots,-3,-2,-1\}\text{.}\) By
Definition 9.1.4 this means that
\(\{\dots,-3,-2,-1\}\) and
\(\N\) have the same cardinality. By
Definition 9.2.5 this means that
\(\{\dots,-3,-2,-1\}\) is countably infinite.