Suppose \(\seq{a_n}{n}\) is a geometric progression. How do we compute its initial term and common ratio? The initial term is the first term in the sequence. The common ratio is the ratio of consecutive terms:
This is also how we can tell if a sequence is a geometric progression. A geometric progression must have the ratio of consecutive terms constant, no matter where we look in the sequence.
The sequence \(\seq{a_n}{n} = 2 \cdot 5^n\) for \(n = 0, 1, 2, \dots\) is a geometric progression with initial term \(a = 2\text{,}\) since \(a_0 = 2 \cdot 5^0 = 2\text{.}\) The common ratio \(r = 5\text{,}\) since
Suppose \(\seq{a_n}{n}\) is an arithmetic progression. How do we compute its initial term and common difference? The initial term is the first term in the sequence. The common difference is the difference of consecutive terms:
\begin{equation*}
a_{n + 1} - a_n = (a + (n + 1)d) - (a + nd) = d.
\end{equation*}
This is also how we can tell if a sequence is an arithmetic progression. An arithmetic progression must have the difference of consecutive terms constant, no matter where we look in the sequence.
The sequence \(\seq{a_n}{n}\) defined by \(a_n = 3 + 5n\) for \(n = 0, 1, 2, \dots\) is an arithmetic progression with initial term \(a = 3\text{,}\) since \(a_0 = 3 + 5 \cdot 0 = 3\text{.}\) The common difference is \(d = 5\text{,}\) since